67th BPSC Prelims Re-exam 2022
General Mental Ability Previous Year Questions (PYQs)
Explore 10 solved 67th BPSC Prelims Re-exam 2022 General Mental Ability questions with detailed step-by-step bilingual solutions, option analysis, and answer keys.
A train of length 140 m is running at a speed of 60 km/hr and a dog is running in the same direction parallel to the train at a speed of 18 km/hr. The train will cross the dog in
Detailed Explanation:
Relative speed = Train speed − Dog speed = 60 − 18 = 42 km/h = 42 × (5/18) = 35/3 m/s.
Time to cross = Length / Relative speed = 140 ÷ (35/3) = 140 × (3/35) = 12 seconds.
Therefore, the train will cross the dog in 12 seconds, making Option 2 the correct answer.
The lengths of the diagonals of a rhombus are 10 cm and 24 cm. Its perimeter is
Detailed Explanation:
Diagonals of a rhombus bisect each other at right angles. Half-diagonals: 5 cm and 12 cm.
Using Pythagoras theorem: Side = √(5² + 12²) = √(25 + 144) = √169 = 13 cm.
Perimeter = 4 × 13 = 52 cm.
Therefore, Option 1 is the correct answer.
Shashi loses 25% by selling oranges at the rate of Rs. 150 per dozen. At what rate should she sell them to get a profit of 20%?
Detailed Explanation:
Selling at Rs. 150 per dozen with 25% loss means SP = 75% of CP. Thus, CP = 150 × (100/75) = Rs. 200 per dozen.
For 20% profit, required SP = 120% of CP = 200 × 1.20 = Rs. 240 per dozen.
Therefore, Option 2 is the correct answer.
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In a mixture of 70 kg, the ratio of sand and cement is 4 ∶ 1. How much sand should be added to the mixture so that the ratio of sand and cement in it becomes 6 ∶ 1?
Detailed Explanation:
Initial mixture: 70 kg with sand:cement = 4:1. Total parts = 5, so 1 part = 14 kg. Sand = 56 kg, cement = 14 kg.
After adding x kg sand: New ratio must be 6:1. So (56 + x)/14 = 6/1. Cross-multiply: 56 + x = 84, hence x = 28 kg.
Therefore, 28 kg of sand must be added, making Option 1 the correct answer.
How many numbers between 100 and 500 are divisible by 4, 5 and 6?
Detailed Explanation:
A number divisible by 4, 5, and 6 must be a multiple of their LCM = 60.
Between 100 and 500, the first multiple of 60 is 120 and the last is 480. The multiples are: 120, 180, 240, 300, 360, 420, 480.
Therefore, there are 7 numbers, making Option 2 the correct answer.
What are the two natural numbers whose product is 2400 and the sum of whose squares is 5200?
Detailed Explanation:
Let the two numbers be A and B. Given AB = 2400 and A² + B² = 5200.
Using identity (A + B)² = A² + B² + 2AB: (A + B)² = 5200 + 2(2400) = 5200 + 4800 = 10000. Therefore, A + B = 100.
Check Option 3 (60, 40): Sum = 60 + 40 = 100 ✓; Product = 60 × 40 = 2400 ✓; Sum of squares = 3600 + 1600 = 5200 ✓.
Therefore, the numbers are 60 and 40, making Option 3 the correct answer.
In a class of 55 students, 34 like to play Cricket and 26 like to play Badminton. Also, each student likes to play at least one of the two games. How many students like to play both Cricket and Badminton?
Detailed Explanation:
Apply the set theory formula: Total = Cricket + Badminton − Both. Given 55 students total, 34 like cricket, 26 like badminton, and each student plays at least one game.
Substitute: 55 = 34 + 26 − Both ⇒ Both = 60 − 55 = 5 students.
Therefore, 5 students like both games, making Option 2 the correct answer.
Anil and Suman together can do a work in 12 days, which Anil alone can do in 20 days. If Suman alone has to do this work, he will take
Detailed Explanation:
Anil's rate: 1/20 work per day. Together rate: 1/12 work per day. Suman's rate = 1/12 − 1/20 = (5−3)/60 = 2/60 = 1/30 work per day.
Alternatively, using combined work formula: (20×y)/(20+y) = 12 → 20y = 240 + 12y → 8y = 240 → y = 30.
Therefore, Suman alone takes 30 days, making Option 3 the correct answer.
At what time between 5 and 6 will the two hands of a watch coincide?
Detailed Explanation:
The hour and minute hands of a clock coincide when the angle between them is 0°. At 5 o'clock, the hour hand is at 150° (30° × 5). The minute hand moves at 6° per minute, while the hour hand moves at 0.5° per minute, creating a relative speed of 5.5° per minute.
To close the 150° gap: M = 150 ÷ 5.5 = 300/11 = 27³⁄₁₁ minutes. This can also be derived using the standard formula for hand coincidence: M = (60H)/11, where H = 5.
Therefore, the hands coincide at 27³⁄₁₁ minutes past 5, making Option 2 the correct answer.
A clock is set right at 6 a.m. It gains 10 minutes in 24 hours. What will be the right time when the clock indicates 11 a.m. on the next day?
Detailed Explanation:
The clock gains 10 minutes in 24 real hours, so in 24 real hours it shows 24 hours 10 minutes. From 6 a.m. to 11 a.m. next day = 29 hours on the fast clock.
If the clock shows 29 hours, real time elapsed = 29 ÷ (24 + 10/60) = 29 ÷ (1450/60) = (29 × 60)/1450 × 24 = 28 hours 48 minutes. Adding this to 6 a.m. gives 10:48 a.m.
Therefore, the correct time is 48 minutes past 10, making Option 1 the correct answer.
67th BPSC Prelims Re-exam 2022 - General Mental Ability Chapter-wise Distribution
Numerical Ability
10 Qs (100%)67th BPSC Prelims Re-exam 2022 - General Mental Ability Questions FAQs
Q1 How many General Mental Ability questions were asked in 67th BPSC Prelims Re-exam 2022?
Q2 What is the chapter-wise question distribution for General Mental Ability in 67th BPSC Prelims Re-exam 2022?
- Numerical Ability: 10 questions (100%)