In a mixture of 70 kg, the ratio of sand and cement is 4 ∶ 1. How much sand should be added to the mixture so that the ratio of sand and cement in it becomes 6 ∶ 1?
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Correct Answer: Option A
Detailed Explanation:
Initial mixture: 70 kg with sand:cement = 4:1. Total parts = 5, so 1 part = 14 kg. Sand = 56 kg, cement = 14 kg.
After adding x kg sand: New ratio must be 6:1. So (56 + x)/14 = 6/1. Cross-multiply: 56 + x = 84, hence x = 28 kg.
Therefore, 28 kg of sand must be added, making Option 1 the correct answer.
Question 1 of 1 Mixture and Alligation
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