BPSC CCE Prelims
Time, Speed, Distance and Work Previous Year Questions (PYQs)
Practice solved questions for Time, Speed, Distance and Work with detailed step-by-step solutions, key insights, and trend analysis for BPSC CCE PRELIMS.
Solved Previous Year Questions
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At what time between 2 and 3 O'Clock will the hands of a clock be together?
Detailed Explanation:
Concept: Clock hands coincide when the minute hand catches up to the hour hand.
At 2:00, the hour hand is at 60° (2 × 30°/hour). The minute hand moves at 6°/minute, the hour hand at 0.5°/minute.
After t minutes: 6t = 60 + 0.5t → 5.5t = 60 → t = 120/11 = 1010/11 minutes past 2.
Anil and Suman together can do a work in 12 days, which Anil alone can do in 20 days. If Suman alone has to do this work, he will take
Detailed Explanation:
Anil's rate: 1/20 work per day. Together rate: 1/12 work per day. Suman's rate = 1/12 − 1/20 = (5−3)/60 = 2/60 = 1/30 work per day.
Alternatively, using combined work formula: (20×y)/(20+y) = 12 → 20y = 240 + 12y → 8y = 240 → y = 30.
Therefore, Suman alone takes 30 days, making Option 3 the correct answer.
A train of length 140 m is running at a speed of 60 km/hr and a dog is running in the same direction parallel to the train at a speed of 18 km/hr. The train will cross the dog in
Detailed Explanation:
Relative speed = Train speed − Dog speed = 60 − 18 = 42 km/h = 42 × (5/18) = 35/3 m/s.
Time to cross = Length / Relative speed = 140 ÷ (35/3) = 140 × (3/35) = 12 seconds.
Therefore, the train will cross the dog in 12 seconds, making Option 2 the correct answer.
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A train 110 m long is travelling at a speed of 58 kmph. The time in which it will pass a passerby walking at 4 kmph in the same direction is
Detailed Explanation:
The relative speed when both move in the same direction is 58 – 4 = 54 kmph = 54 × (5/18) = 15 m/s.
Time = Distance / Relative Speed = 110 / 15 = 22/3 = 7⅓ seconds.
Therefore, the train will pass the passerby in 7⅓ seconds, making Option 3 the correct answer.
in a 100 m race, A runs at 8 kmph. If A gives B a start of 4 m and still beats him by 15 seconds, what is the speed of B?
Detailed Explanation:
A's speed = 8 kmph = 8 × (5/18) = 20/9 m/s. A covers 100 m in 100 ÷ (20/9) = 45 seconds.
B gets a 4 m head start, so B runs only 96 m. A beats B by 15 seconds, meaning B takes 45 + 15 = 60 seconds to cover 96 m.
B's speed = 96/60 = 1.6 m/s = 1.6 × (18/5) = 5.76 kmph.
Therefore, Option 2 (5.76 kmph) is the correct answer.
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