There are two chemicals which do not react with each other. A container contains $10$ litres of the chemical $A$. One litre of this chemical is removed from it and one litre of the chemical $B$ is poured. Then one litre of the mixture is removed from the container and one litre of $B$ is poured. If this process of replacing one litre of the mixture by one litre of $B$ is performed once more, then what is the volume of $B$ that is present in the container approximately (in percentage)?
Detailed Explanation:
After each replacement of 1 litre from 10 litres, the fraction of chemical A remaining is (9/10). After 3 replacements, the amount of A left is: 10 × (9/10)³ = 10 × 729/1000 = 7.29 litres.
Since the total volume remains 10 litres, chemical B = 10 – 7.29 = 2.71 litres, which is 27.1% ≈ 27%.
Therefore, the volume of B is approximately 27%, making Option 2 the correct answer.
Question 1 of 2 Mixture & Alligation
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