An alloy $P$ contains $20%$ copper and $80%$ zinc by weight. Another alloy $Q$ contains $60%$ copper and $40%$ zinc by weight. A third alloy $R$ is to be prepared from $P$ and $Q$ so that it contains equal amount of copper and zinc. In what ratio, amounts of $P$ and $Q$ be mixed in order to get $R$?
Detailed Explanation:
Use alligation method: Copper in P = 20%, in Q = 60%, desired in R = 50% (equal copper and zinc).
Ratio of P to Q = (60 - 50) : (50 - 20) = 10 : 30 = 1 : 3.
Therefore, P and Q must be mixed in the ratio 1:3, making Option 1 the correct answer.
Question 2 of 2 Mixture & Alligation
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