X travels 6 km on a bicycle with average speeds of 5 km per hour, 10 km per hour and 4 km per hour during the first 1 km, the next 2 km and the remaining 3 km, respectively. Y travels the same distances with average speeds of 4 km per hour, 10 km per hour and 5 km per hour, respectively. How many minutes early will Y complete the journey if both X and Y start at the same time?
Detailed Explanation:
X's journey: Time = 1/5 + 2/10 + 3/4 = 0.2 + 0.2 + 0.75 = 1.15 hours = 69 minutes.
Y's journey: Time = 1/4 + 2/10 + 3/5 = 0.25 + 0.2 + 0.6 = 1.05 hours = 63 minutes.
Therefore, Y completes the journey 69 - 63 = 6 minutes earlier, making Option 4 the correct answer.
Question 5 of 5 Time, Speed & Distance
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