UPSC CSE Prelims
Ranking & Ordering Previous Year Questions (PYQs)
Practice solved questions for Ranking & Ordering with detailed step-by-step solutions, key insights, and trend analysis for UPSC CSE PRELIMS.
Solved Previous Year Questions
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A pattern formed by two characters $a$ and $b$ is repeated more than once in the following string :
$x , b , x , a , x , a , x , x , a , x , a , x , b , a , b$
What is $x , x$ in the 7th and 8th positions from the left in the above string?
Detailed Explanation:
The string has 15 positions. A pattern repeated more than once with length 5 fits perfectly (repeated 3 times).
The last 5 known characters are: a, x, b, a, b. Testing this as the repeating pattern and solving for x values: the pattern must be a, b, b, a, b.
Repeating a, b, b, a, b three times gives: a, b, b, a, b, a, b, b, a, b, a, b, b, a, b. Positions 7 and 8 are both b.
Therefore, x, x at positions 7 and 8 is bb, making Option 4 the correct answer.
P, Q, R, S and T are ranked 1 to 5 (not necessarily in that order). The rank of P is 4, the rank of Q is not 5, the rank of R is 1, the rank of S is not 2, the rank of T is not
- Then which of the following is/are correct? I. If the rank of S is 3, then that of T is
- II. If the rank of Q is 3, then that of T is
- Select the answer using the
code given below.
Detailed Explanation:
Given: P=4, R=1, Q≠5, S≠2, T≠3. Remaining ranks {2,3,5} must be assigned to Q, S, T.
- Statement I: If S=3, then Q and T take {2,5}. Since Q≠5, Q=2 and T=5. Thus T=5, not 2. Statement I is incorrect.
- Statement II: If Q=3, then S and T take {2,5}. Since S≠2, S=5 and T=2. Thus T=2, not 5. Statement II is incorrect.
- Therefore, both statements are incorrect, making Option 4 the correct answer.
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