If $x$ and $y$ are integers, then is $x$ even? Statement I : $x^2 y^2$ is even. Statement II : $1 + x^2 + y^2$ is odd.
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Correct Answer: Option C
Detailed Explanation:
We need to determine if x is even.
- Statement I (x²y² is even): At least one of x or y is even, but x could be odd (y even) or even (y odd/even) — insufficient alone.
- Statement II (1 + x² + y² is odd): x² + y² must be even, so x and y have the same parity (both even or both odd) — insufficient alone.
- Combining both: At least one is even (Statement I) and both have same parity (Statement II) → both x and y must be even.
- Therefore, both statements together uniquely determine that x is even, making Option 3 the correct answer.
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Three variables $x$, $y$ and $z$ take values $2, 3, 4$ or $5$ such that their values...
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